A submerged wreck, mass $10^{4} \mathrm{~kg}$ and mean density $8 \times 10^{3} \mathrm{~kg} \mathrm{~m}^{-3}$, is lifted out of the water by a crane with a steel cable $10 \mathrm{~m}$ long, cross-sectional area $5 \mathrm{~cm}^{2}$ and Young's modulus $5 \times 10^{10} \mathrm{~N} \mathrm{~m}^{-2}$. Determine the change in the extension of the cable as the wreck is lifted clear of the water. [5]
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- The change in extension as the wreck clears the water is $\approx 4.9\,\mathrm{mm}$, set entirely by the loss of the buoyant force $F_{\text{buoyant}}=\rho_w V g$; the weight cancels in the difference.
Worked solutions are in the book.
