A lithium surface, with work function energy $\mathrm{W}=3.7 \times 10^{-19} \mathrm{~J}$, is irradiated with photons of frequency $f=6.3 \times 10^{14} \mathrm{~Hz}$. The loss of photoelectrons from the surface causes the metal to acquire a positive potential, $V$. What will this potential be when the metal prevents the loss of further electrons? [4]
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- The surface charges positively until its potential equals the maximum kinetic energy per unit charge, $V = K_{\text{max}}/e \approx 0.30 \, \mathrm{V}$, at which point even the fastest electrons can no longer escape.
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