The energy levels, $E_{n}$, of the hydrogen atom are given by
$$ E_{n}=\frac{-2.16 \times 10^{-18}}{n^{2}} \mathrm{~J}, \text { where } n \text { is a positive integer. } $$
(i) What is the ionization energy of the atom?
(ii) What is the wavelength of the $\mathrm{H}_{\alpha}$ line, which is due to transitions from the $n=3$ to $n=2$ level? [4]
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- The ionization energy of the hydrogen atom is $2.16 \times 10^{-18} \, \mathrm{J}$.
Worked solutions are in the book.