A proton travelling with a velocity of $3.00 \times 10^{7} \mathrm{~m} \mathrm{~s}^{-1}$ collides with an oxygen nucleus, of mass $2.56 \times 10^{-26} \mathrm{~kg}$ that is at rest, and is scattered through an angle of $90^{\circ}$. Calculate the velocity and direction of the oxygen nucleus using Newtonian mechanics. [12]
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- The oxygen recoils at $\approx 2.68 \times 10^{6}\,\mathrm{m/s}$, $43.1^\circ$ below the incident line.
Worked solutions are in the book.
