The electron gun of a cathode ray tube consists of a small hot filament $\mathrm{F}$ which is located at $x=0$, Figure, and which produces electrons in the $\mathrm{x}-\mathrm{y}$ plane of the page with a very small range of velocities. A typical electron has velocity components $v_{x}$ and $v_{y}$. Between $x=0$ and $x=d$ there is a horizontal uniform electric field, $E$, which accelerates the electrons produced at the filament to velocities which are much greater than $v_{x}$ and $v_{y}$. The electrons emerge from the field, beyond $x=d$, travelling in straight lines. Show that the paths of the emerging electrons, when projected back, appear to have come from a point along the axis at approximately $x=-d$. [6]

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- The result $x=-d$ is exact in the limit $v_x' \gg v_x$: because a uniformly accelerated body covers half the distance of one moving at its final speed for the same time, the back-projection overshoots the entry point by exactly $d$.
Worked solutions are in the book.

