The displacement of an object is determined by the following function:
$$ s=2 t^{3}-9 t^{2}+12 t+4 $$
where $s$ is the displacement in metres, and $t$ the time elapsed in seconds. Determine
(i) the times when the object comes to rest,
(ii) the time when the acceleration is zero,
(iii) the object's velocity when its acceleration is zero,
(iv) the object's accelerations when its velocity is zero. [4]
Show answer · 显示答案
- The object is momentarily at rest at $t=1\,\text{s}$ and $t=2\,\text{s}$; between these it moves backwards ($v<0$, as confirmed by $v(1.5) = -1.5\,\text{m/s}$).
Worked solutions are in the book.