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M8 · 万有引力与圆周运动M8 · Gravitation & Circular Motion
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题型概述:万有引力、轨道与圆周运动Question type: gravitation, orbits & circular motion

Top Gold这是 BPhO Round 1 最稳定的考点之一:Section 1 每年 1–3 道小题(每题 2–5 分),Section 2 还常有整道大题,合计约 15 分/年。物理本身只有两条主线——"引力提供向心力"和"合力指向圆心"。失分几乎都出在三处:单位换算(km/h、光年、天 → 秒)、半径从哪里量(从球心 / 从转轴),以及角度从哪条线量(竖直还是水平,sin 还是 tan)。One of the most reliable topics in BPhO Round 1: Section 1 has 1–3 short items every year (2–5 marks each) and Section 2 often has a full question, about 15 marks a year in total. The physics is just two ideas: "gravity supplies the centripetal force" and "the net force points to the centre". Marks are lost in three places: unit conversions (km/h, light years, days → seconds), where the radius is measured from (the centre of the planet / the axis), and which line the angle is measured from (vertical or horizontal, sin or tan).

1万有引力与表面重力加速度 gNewton's law of gravitation and surface g

两个质点(或均匀球体,按球心算)之间的引力与质量乘积成正比、与距离平方成反比。放在星球表面的物体所受引力除以质量就是 g。把质量写成"密度 × 体积"后,表面 g 只和 ρR 成正比——这正是"比值题"最常用的一步。Two point masses (or uniform spheres, measured centre to centre) attract with a force proportional to the product of the masses and inversely proportional to the square of the distance. Divide the force on a surface object by its mass to get g. Writing the mass as "density × volume" shows that surface g is proportional to ρR alone — the key step in most ratio questions.

F = GMm/r²,    g(r) = GM/r² = g0(R/r)²,    gsurface = G·(4/3)πR³ρ/R² = (4/3)πGρ R

r 永远从星球球心量起:高度 h 处 r = R + h。比值题里 G、π 全部约掉,不必代数值。r is always measured from the centre of the planet: at height h, r = R + h. In ratio questions G and π cancel, so no numbers are needed for them.

2圆轨道:v、T 与开普勒第三定律Circular orbits: v, T and Kepler's third law

卫星做匀速圆周运动,引力就是向心力。令 GMm/r² = mv²/r = mω²r,卫星质量 m 约掉,得到轨道速度和周期只由中心天体质量 M 和轨道半径 r 决定。越远越慢、周期越长;T² ∝ r³ 就是开普勒第三定律(等价写法 ω²r³ = GM = 常量)。A satellite moves in uniform circular motion and gravity is the centripetal force. Setting GMm/r² = mv²/r = mω²r, the satellite mass m cancels: the orbital speed and period depend only on the central mass M and the radius r. Further out means slower and longer; T² ∝ r³ is Kepler's third law (equivalently ω²r³ = GM = constant).

v = 2πr/T = √(GM/r),    T² = (4π²/GM) r³,    a = v²/r = ω²r = GM/r²

地球同步轨道:T = 1 恒星日(23.93 h),代入得 r ≈ 42 200 km ≈ 6.6 R⊕,只能在赤道上空。拖动下面的滑块比较近地轨道和同步轨道。Geostationary orbit: T = 1 sidereal day (23.93 h) gives r ≈ 42 200 km ≈ 6.6 R⊕, and it must lie above the equator. Use the slider below to compare a low orbit with the geostationary one.

俯视北极,地球与轨道按比例View from above the N pole, to scale
轨道半径 rOrbit radius r
离地高度Altitude—
轨道速度 vOrbital speed v—
周期 TPeriod T—
该处 gg at this r—

动画 1 s = 2 h。地球上的红点随地球自转;选"地球同步轨道"时卫星始终停在红点正上方。Animation: 1 s = 2 h. The red dot turns with the Earth; in the geostationary orbit the satellite stays above it.

3圆周运动的受力:合力指向圆心Forces in circular motion: the net force points to the centre

"向心力"不是一个新的力,它是真实受力(重力、拉力、支持力、摩擦力……)的合力在指向圆心方向上的分量。受力图里只画真实的力,再令"指向圆心的合力 = mv²/r"。最常见的一族是斜支撑:圆锥摆的绳、倾斜轨道的支持力、转弯时自行车的倾斜——竖直分量托住重力,水平分量提供向心力,两式相除得到同一个公式。竖直圆周(过山车、绳球)则在最高点取临界条件,再用能量守恒连接最高点和最低点。"Centripetal force" is not a new force: it is the component, towards the centre, of the resultant of the real forces (weight, tension, normal reaction, friction …). Draw only real forces, then set "net force towards the centre = mv²/r". The most common family is the tilted support: a conical-pendulum string, the normal force on a banked track, a leaning cyclist — the vertical component holds up the weight, the horizontal component supplies the centripetal force, and dividing the two gives one formula. For vertical circles (loops, a ball on a string) use the critical condition at the top, then link top and bottom with energy conservation.

F cos θ = mg,   F sin θ = mv²/r  ⇒  tan θ = v²/(rg) = ω²r/g      竖直圆最高点top of a vertical circle: vtop² ≥ gr

θ 是支撑力(绳、法向力)与竖直方向的夹角。地球自转也属于这一类:赤道上"视重" = mg − mω²R,所以赤道的 g 比两极小约 0.34%。θ is the angle between the support force (string, normal reaction) and the vertical. The Earth's spin belongs here too: apparent weight at the equator = mg − mω²R, so g is about 0.34% smaller at the equator than at the poles.

子题型Sub-type识别特征How to spot it核心步骤Core step真题Past paper
轨道速度 v = 2πr/TOrbital speed v = 2πr/T给出轨道半径和周期,单位是光年、秒差距、年Radius and period given in light years, parsecs, years每个轨道 v = 2πr/T;比值中 2π 约掉,统一"光距离/年"v = 2πr/T for each orbit; 2π cancels in the ratio; use light-distance per year2024 Q1(b)
开普勒第三定律比值Kepler III ratios同一中心天体的两颗卫星,给周期比Two satellites of the same body, period ratio givenT² ∝ r³ 求半径比,再用 a = ω²r 或 GM/r²T² ∝ r³ for the radius ratio, then a = ω²r or GM/r²2022 Q1(d)
其他星球 / 高空的 gg on other planets / at altitude"density … radius … times that of the Earth""density … radius … times that of the Earth"g ∝ ρR(表面)或 g ∝ M/r²g ∝ ρR (surface) or g ∝ M/r²2018 Q1(k)
圆锥摆Conical pendulum绳与竖直成 θ,物体在水平圆上转String at θ to the vertical, mass on a horizontal circle竖直平衡 + 水平向心,tanθ = rω²/gVertical balance + horizontal centripetal: tanθ = rω²/g2024 Q1(d)
倾斜弯道 / 骑车倾斜Banked curve / leaning cyclist"banked"、"only a normal reaction"、"leans over""banked", "only a normal reaction", "leans over"tanθ = v²/(rg),再处理几何(h = d sinθ)tanθ = v²/(rg), then geometry (h = d sinθ)2021 Q1(l);同型 2022(c); same type 2022(c)
竖直圆周 / 地球自转视重Vertical circles / apparent weight on a spinning Earth"top of the loop"、"tension is zero"、"equator""top of the loop", "tension is zero", "equator"最高点 mg ≤ mv²/r,能量守恒连两端;视重 = mg − mv²/RAt the top mg ≤ mv²/r, energy links top and bottom; apparent weight = mg − mv²/R2017(k)、2016(q)、2019(m)、2015(k)(本模块未单列)2017(k), 2016(q), 2019(m), 2015(k) (not included here)

题目:BPhO Round 1 Section 1 真题原文。解答由教研组整理,所有数值均独立复核。Questions: BPhO Round 1 Section 1, original wording. Solutions prepared in-house; every number independently re-checked.